PHP日期函数date格式化UNIX时间的方法

本文实例讲述了PHP日期函数date格式化UNIX时间的方法。分享给大家供大家参考。具体分析如下：

日期函数可以根据指定的格式将一个unix时间格式化成想要的文本输出

使用到函数语法如下

string date (string $Format);string date (string $Format, int $Time);

下面是演示代码

<?phpecho "When this page was loaded,";echo "It was then ", date ("r"), "";echo "The currend date was ", date ("F j, Y"), "";echo "The currend date was ", date ("M j, Y"), "";echo "The currend date was ", date ("m/d/y"), "";echo "The currend date was the ", date ("jS of M, Y"), "";echo "The currend time was ", date ("g:i:s A T"), "";echo "The currend time was ", date ("H:i:s O"), "";echo date ("Y");date ("L")?(print " is"):(print " is not");echo " a leap year";echo time ("U"), " seconds had elapsed since January 1, 1970.";?>

输出结果如下

It was then Sat, 26 Dec 2009 07:09:51 +0000The currend date was December 26, 2009The currend date was Dec 26, 2009The currend date was 12/26/09The currend date was the 26th of Dec, 2009The currend time was 7:09:51 AM GMTThe currend time was 07:09:51 +00002009 is not a leap year1261811391 seconds had elapsed since January 1, 1970.

希望本文所述对大家的php程序设计有所帮助。