不废话了,直接给大家贴代码了,代码很简单,都是比较常见的sql语句,具体内容请看下文。

CREATE TABLE `test_avatar` ( `uid` int(11) unsigned NOT NULL DEFAULT "0", `avatar` varchar(255) NOT NULL DEFAULT "", PRIMARY KEY (`uid`)) ENGINE=MyISAM DEFAULT CHARSET=utf8;INSERT INTO `test_avatar` VALUES (1,"./Uploads/admin.jpg");CREATE TABLE `test_pro` ( `id` int(11) unsigned NOT NULL AUTO_INCREMENT, `uid` int(11) unsigned NOT NULL DEFAULT "0", `name` varchar(255) NOT NULL DEFAULT "", PRIMARY KEY (`id`)) ENGINE=MyISAM DEFAULT CHARSET=utf8;INSERT INTO `test_pro` VALUES (1,1,"产品1"),(2,1,"产品2");CREATE TABLE `test_user` ( `id` int(11) unsigned NOT NULL AUTO_INCREMENT, `username` varchar(50) NOT NULL DEFAULT "", `tel` int(11) unsigned NOT NULL DEFAULT "0", PRIMARY KEY (`id`)) ENGINE=MyISAM DEFAULT CHARSET=utf8;INSERT INTO `test_user` VALUES (1,"admin",110);

如上三个表:用户头像表、产品表、用户表

怎样在模型中建立关联?

class ProModel extends RelationModel{ protected $_link=array( "Avatar"=>array( "mapping_type"=>self::HAS_ONE, "class_name"=>"Avatar", "foreign_key"=>"uid", "mapping_fields"=>"avatar", "as_fields"=>"avatar", ),  )}

试过用HAS_ONE、BELONGS_TO、HAS_MANY、MANY_TO_MANY都不行,求大神指点

------解决思路----------------------

Model下建立ProModelModel.class.php

class ProModelModel extends ViewModel {  public $viewFields = array(   "test_avatar"=>array( "id",... ),   "test_pror"=>array( "id",... "_on"=>"" ),      "test_pror"=>array( "id",... "_on"=>"" ),  ); }

Thinkphp中SQL语句有关问题及解决办法

请问,在THINKPHP中,数据表里有个字段,字段的内容形式为 {1,2,3,4,5}

那么SQL语句里怎么将获得的ID值来跟字段里的内容来比较呢

------解决思路----------------------

用模糊查询吧

$where = array("该字段"=>array("LIKE", "%" . $ID . "%"));