本文实例讲述了PHP响应post请求上传文件的方法。分享给大家供大家参考,具体如下:
function send_file($url, $post = "", $file = "") { $eol = ""; $mime_boundary = md5 ( time () ); $data = ""; $confirmation = ""; date_default_timezone_set ( "Asia/Shanghai" ); $time = date ( "Y-m-d H:i:s " ); $post ["filename"] = $file [filename]; foreach ( $post as $key => $value ) { $data .= "--" . $mime_boundary . $eol; $data .= "Content-Disposition: form-data; "; $data .= "name=" . $key . $eol . $eol; $data .= $value . $eol; } $data .= "--" . $mime_boundary . $eol; $data .= "Content-Disposition: form-data; name=" . $file [name] . "; filename=" . $file [filename] . $eol; $data .= "Content-Type: text/plain" . $eol; $data .= "Content-Transfer-Encoding: binary" . $eol . $eol; $data .= $file [filedata] . $eol; $data .= "--" . $mime_boundary . "--" . $eol . $eol; $params = array ("http" => array ("method" => "POST", "header" => "Content-Type: multipart/form-data;boundary=" . $mime_boundary . $eol, "content" => $data ) ); $ctx = stream_context_create ( $params ); $response = file_get_contents ( $url, FILE_TEXT, $ctx ); return $response;}希望本文所述对大家PHP程序设计有所帮助。