本文实例讲述了PHP响应post请求上传文件的方法。分享给大家供大家参考,具体如下:

function send_file($url, $post = "", $file = "") {  $eol = "";  $mime_boundary = md5 ( time () );  $data = "";  $confirmation = "";  date_default_timezone_set ( "Asia/Shanghai" );  $time = date ( "Y-m-d H:i:s " );  $post ["filename"] = $file [filename];  foreach ( $post as $key => $value ) {    $data .= "--" . $mime_boundary . $eol;    $data .= "Content-Disposition: form-data; ";    $data .= "name=" . $key . $eol . $eol;    $data .= $value . $eol;  }  $data .= "--" . $mime_boundary . $eol;  $data .= "Content-Disposition: form-data; name=" . $file [name] . "; filename=" . $file [filename] . $eol;  $data .= "Content-Type: text/plain" . $eol;  $data .= "Content-Transfer-Encoding: binary" . $eol . $eol;  $data .= $file [filedata] . $eol;  $data .= "--" . $mime_boundary . "--" . $eol . $eol;  $params = array ("http" => array ("method" => "POST", "header" => "Content-Type: multipart/form-data;boundary=" . $mime_boundary . $eol, "content" => $data ) );  $ctx = stream_context_create ( $params );  $response = file_get_contents ( $url, FILE_TEXT, $ctx );  return $response;}

希望本文所述对大家PHP程序设计有所帮助。